
It didn't look as neat as the previous solution, but it does show us that there is more than one way to set up and solve matrix equations. What Is a 3x3 System of Linear Equations To define a 3x3 system of linear equations we need to understand what each part of the term means. In fact it is just like the Inverse we got before, but Transposed (rows and columns swapped over). This online 3×3 System of Linear Equations Calculator solves a system of 3 linear equations with 3 unknowns using Cramer’s rule. Then (also shown on the Inverse of a Matrix page) the solution is this: This calculator is designed to solve systems of three linear equations. 3×3 System of Linear Equations Calculator. 3x3-12x2+27x Final result : 3x (x2 - 4x + 9) Reformatting the input. The rows and columns have to be switched over ("transposed"): Solving linear equations and linear inequalities Lesson (article) Khan Academy. I want to show you this way, because many people think the solution above is so neat it must be the only way.Īnd because of the way that matrices are multiplied we need to set up the matrices differently now. Do It Again!įor fun (and to help you learn), let us do this all again, but put matrix "X" first. Quite neat and elegant, and the human does the thinking while the computer does the calculating. Just like on the Systems of Linear Equations page. 3×3 System of Equations Calculator Enter a system of three linear equations to find its solution. Then multiply A -1 by B (we can use the Matrix Calculator again): (I left the 1/determinant outside the matrix to make the numbers simpler) Also you can compute a number of solutions in a system (analyse the compatibility) using RouchCapelli theorem. It means that we can find the X matrix (the values of x, y and z) by multiplying the inverse of the A matrix by the B matrix.įirst, we need to find the inverse of the A matrix (assuming it exists!) This calculator solves Systems of Linear Equations with steps shown, using Gaussian Elimination Method, Inverse Matrix Method, or Cramer's rule. Then (as shown on the Inverse of a Matrix page) the solution is this:

A is the 3x3 matrix of x, y and z coefficients.

Which is the first of our original equations above (you might like to check that).

Why does go there? Because when we Multiply Matrices we use the "Dot Product" like this:
